Base | Representation |
---|---|
bin | 1001000110001000101010… |
… | …1101101100100111110011 |
3 | 1022102002100122210110110222 |
4 | 2101202022231230213303 |
5 | 2302324032320201042 |
6 | 33134222344243255 |
7 | 2051356243506164 |
oct | 221421255544763 |
9 | 38362318713428 |
10 | 10001011100147 |
11 | 3206450049581 |
12 | 115631a47052b |
13 | 577125780c32 |
14 | 2680a152976b |
15 | 125238ab82d2 |
hex | 9188ab6c9f3 |
10001011100147 has 2 divisors, whose sum is σ = 10001011100148. Its totient is φ = 10001011100146.
The previous prime is 10001011100131. The next prime is 10001011100159. The reversal of 10001011100147 is 74100111010001.
10001011100147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10001011100147 - 24 = 10001011100131 is a prime.
It is not a weakly prime, because it can be changed into another prime (10001011100177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5000505550073 + 5000505550074.
It is an arithmetic number, because the mean of its divisors is an integer number (5000505550074).
Almost surely, 210001011100147 is an apocalyptic number.
10001011100147 is a deficient number, since it is larger than the sum of its proper divisors (1).
10001011100147 is an equidigital number, since it uses as much as digits as its factorization.
10001011100147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28, while the sum is 17.
Adding to 10001011100147 its reverse (74100111010001), we get a palindrome (84101122110148).
The spelling of 10001011100147 in words is "ten trillion, one billion, eleven million, one hundred thousand, one hundred forty-seven".
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