Base | Representation |
---|---|
bin | 1001000110101110010000… |
… | …1000011101010011100000 |
3 | 1022110001101212010202200220 |
4 | 2101223210020131103200 |
5 | 2303010213403101422 |
6 | 33143011510443040 |
7 | 2052164264232324 |
oct | 221534410352340 |
9 | 38401355122626 |
10 | 10011101222112 |
11 | 320a758718551 |
12 | 1158275663480 |
13 | 5780730339c3 |
14 | 26877b62b984 |
15 | 125629828e5c |
hex | 91ae421d4e0 |
10011101222112 has 96 divisors (see below), whose sum is σ = 26777742983712. Its totient is φ = 3273732194304.
The previous prime is 10011101222093. The next prime is 10011101222123. The reversal of 10011101222112 is 21122210111001.
It is a happy number.
It is a tau number, because it is divible by the number of its divisors (96).
It is a junction number, because it is equal to n+sod(n) for n = 10011101222091 and 10011101222100.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 51683908 + ... + 51877244.
It is an arithmetic number, because the mean of its divisors is an integer number (278934822747).
Almost surely, 210011101222112 is an apocalyptic number.
10011101222112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 10011101222112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (13388871491856).
10011101222112 is an abundant number, since it is smaller than the sum of its proper divisors (16766641761600).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
10011101222112 is a wasteful number, since it uses less digits than its factorization.
10011101222112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 203580 (or 203572 counting only the distinct ones).
The product of its (nonzero) digits is 16, while the sum is 15.
Adding to 10011101222112 its reverse (21122210111001), we get a palindrome (31133311333113).
Subtracting 10011101222112 from its reverse (21122210111001), we obtain a square (11111108888889 = 33333332).
It can be divided in two parts, 1001110 and 1222112, that added together give a palindrome (2223222).
The spelling of 10011101222112 in words is "ten trillion, eleven billion, one hundred one million, two hundred twenty-two thousand, one hundred twelve".
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