Base | Representation |
---|---|
bin | 11101001001000110110… |
… | …00110111111100011011 |
3 | 10112201120210022102021122 |
4 | 32210203120313330123 |
5 | 112401201200300011 |
6 | 2044000042155455 |
7 | 132225445641446 |
oct | 16444330677433 |
9 | 3481523272248 |
10 | 1001321103131 |
11 | 356726727268 |
12 | 1420904b2b8b |
13 | 73568bb207b |
14 | 3666da9c65d |
15 | 1b0a77243db |
hex | e923637f1b |
1001321103131 has 2 divisors, whose sum is σ = 1001321103132. Its totient is φ = 1001321103130.
The previous prime is 1001321103121. The next prime is 1001321103143. The reversal of 1001321103131 is 1313011231001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1001321103131 - 210 = 1001321102107 is a prime.
It is a super-2 number, since 2×10013211031312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1001321103121) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500660551565 + 500660551566.
It is an arithmetic number, because the mean of its divisors is an integer number (500660551566).
Almost surely, 21001321103131 is an apocalyptic number.
1001321103131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1001321103131 is an equidigital number, since it uses as much as digits as its factorization.
1001321103131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 1001321103131 its reverse (1313011231001), we get a palindrome (2314332334132).
The spelling of 1001321103131 in words is "one trillion, one billion, three hundred twenty-one million, one hundred three thousand, one hundred thirty-one".
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