Base | Representation |
---|---|
bin | 10110110010010001110010… |
… | …101111111100100001000111 |
3 | 111010211011221200212200112221 |
4 | 112302101302233330201013 |
5 | 101113333341120342133 |
6 | 553044445411153211 |
7 | 30052041211342366 |
oct | 2662216257744107 |
9 | 433734850780487 |
10 | 100212102121543 |
11 | 29a2679413a415 |
12 | b2a593a2a5807 |
13 | 43bbc64803c89 |
14 | 1aa64122d57dd |
15 | b8bb30437a2d |
hex | 5b2472bfc847 |
100212102121543 has 2 divisors, whose sum is σ = 100212102121544. Its totient is φ = 100212102121542.
The previous prime is 100212102121519. The next prime is 100212102121601. The reversal of 100212102121543 is 345121201212001.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-100212102121543 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100212102101543) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50106051060771 + 50106051060772.
It is an arithmetic number, because the mean of its divisors is an integer number (50106051060772).
Almost surely, 2100212102121543 is an apocalyptic number.
100212102121543 is a deficient number, since it is larger than the sum of its proper divisors (1).
100212102121543 is an equidigital number, since it uses as much as digits as its factorization.
100212102121543 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 960, while the sum is 25.
Adding to 100212102121543 its reverse (345121201212001), we get a palindrome (445333303333544).
The spelling of 100212102121543 in words is "one hundred trillion, two hundred twelve billion, one hundred two million, one hundred twenty-one thousand, five hundred forty-three".
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