10034331431 has 4 divisors (see below), whose sum is σ = 10279071264. Its totient is φ = 9789591600.

The previous prime is 10034331401. The next prime is 10034331467. The reversal of 10034331431 is 13413343001.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13413343001 = 29 ⋅462529069.

It is a cyclic number.

It is not a de Polignac number, because 10034331431 - 2²⁶ = 9967222567 is a prime.

It is a super-2 number, since 2×10034331431² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10034331397 and 10034331406.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10034331401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 122369855 + ... + 122369936.

It is an arithmetic number, because the mean of its divisors is an integer number (2569767816).

Almost surely, 2^10034331431 is an apocalyptic number.

10034331431 is a deficient number, since it is larger than the sum of its proper divisors (244739833).

10034331431 is an equidigital number, since it uses as much as digits as its factorization.

10034331431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 244739832.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 10034331431 its reverse (13413343001), we get a palindrome (23447674432).

The spelling of 10034331431 in words is "ten billion, thirty-four million, three hundred thirty-one thousand, four hundred thirty-one".