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100404313131 = 361754243281
BaseRepresentation
bin101110110000010010…
…0000011110000101011
3100121011100102120121010
41131200210003300223
53121112001010011
6114043004515003
710153053402663
oct1354044036053
9317140376533
10100404313131
1139643687591
121756124ba63
139611501295
144c06a291a3
1529299a11a6
hex1760903c2b

100404313131 has 8 divisors (see below), whose sum is σ = 134089393104. Its totient is φ = 66827720960.

The previous prime is 100404313117. The next prime is 100404313147. The reversal of 100404313131 is 131313404001.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 100404313131 - 25 = 100404313099 is a prime.

It is a super-2 number, since 2×1004043131312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 100404313098 and 100404313107.

It is not an unprimeable number, because it can be changed into a prime (100404313111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 27119790 + ... + 27123491.

It is an arithmetic number, because the mean of its divisors is an integer number (16761174138).

Almost surely, 2100404313131 is an apocalyptic number.

100404313131 is a deficient number, since it is larger than the sum of its proper divisors (33685079973).

100404313131 is an equidigital number, since it uses as much as digits as its factorization.

100404313131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 54243901.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 100404313131 its reverse (131313404001), we get a palindrome (231717717132).

The spelling of 100404313131 in words is "one hundred billion, four hundred four million, three hundred thirteen thousand, one hundred thirty-one".