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10053903 = 33351301
BaseRepresentation
bin100110010110…
…100100001111
3200220210100210
4212112210033
510033211103
6555253503
7151312446
oct46264417
920823323
1010053903
115747712
12344a293
132110272
141499d5d
15d38e03
hex99690f

10053903 has 4 divisors (see below), whose sum is σ = 13405208. Its totient is φ = 6702600.

The previous prime is 10053887. The next prime is 10053913. The reversal of 10053903 is 30935001.

10053903 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 10053903 - 24 = 10053887 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 10053903.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10053913) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1675648 + ... + 1675653.

It is an arithmetic number, because the mean of its divisors is an integer number (3351302).

Almost surely, 210053903 is an apocalyptic number.

10053903 is a deficient number, since it is larger than the sum of its proper divisors (3351305).

10053903 is an equidigital number, since it uses as much as digits as its factorization.

10053903 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3351304.

The product of its (nonzero) digits is 405, while the sum is 21.

The square root of 10053903 is about 3170.7890185252. The cubic root of 10053903 is about 215.8298771909.

Adding to 10053903 its reverse (30935001), we get a palindrome (40988904).

The spelling of 10053903 in words is "ten million, fifty-three thousand, nine hundred three".

Divisors: 1 3 3351301 10053903