101000000486713 has 2 divisors, whose sum is σ = 101000000486714. Its totient is φ = 101000000486712.

The previous prime is 101000000486647. The next prime is 101000000486729. The reversal of 101000000486713 is 317684000000101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 93942094371129 + 7057906115584 = 9692373^2 + 2656672^2 .

It is a cyclic number.

It is not a de Polignac number, because 101000000486713 - 2¹⁷ = 101000000355641 is a prime.

It is not a weakly prime, because it can be changed into another prime (101000000486783) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50500000243356 + 50500000243357.

It is an arithmetic number, because the mean of its divisors is an integer number (50500000243357).

Almost surely, 2^{101000000486713} is an apocalyptic number.

It is an amenable number.

101000000486713 is a deficient number, since it is larger than the sum of its proper divisors (1).

101000000486713 is an equidigital number, since it uses as much as digits as its factorization.

101000000486713 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4032, while the sum is 31.

Adding to 101000000486713 its reverse (317684000000101), we get a palindrome (418684000486814).

The spelling of 101000000486713 in words is "one hundred one trillion, four hundred eighty-six thousand, seven hundred thirteen".