10100000111 has 2 divisors, whose sum is σ = 10100000112.
Its totient is φ = 10100000110.
The previous prime is 10100000087. The next prime is 10100000129. The reversal of 10100000111 is 11100000101.
It is a strong prime.
It is an emirp because it is prime and its reverse (11100000101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10100000111 - 210 = 10099999087 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10100000095 and 10100000104.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10100000011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5050000055 + 5050000056.
It is an arithmetic number, because the mean of its divisors is an integer number (5050000056).
Almost surely, 210100000111 is an apocalyptic number.
10100000111 is a deficient number, since it is larger than the sum of its proper divisors (1).
10100000111 is an equidigital number, since it uses as much as digits as its factorization.
10100000111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1, while the sum is 5.
Adding to 10100000111 its reverse (11100000101), we get a palindrome (21200000212).
The spelling of 10100000111 in words is "ten billion, one hundred million, one hundred eleven", and thus it is an aban number.