1010441213131 has 16 divisors (see below), whose sum is σ = 1167013149120. Its totient is φ = 856929945600.

The previous prime is 1010441213129. The next prime is 1010441213143. The reversal of 1010441213131 is 1313121440101.

It is a cyclic number.

It is not a de Polignac number, because 1010441213131 - 2¹ = 1010441213129 is a prime.

It is a super-2 number, since 2×1010441213131² (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1010441219131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2311935 + ... + 2714023.

It is an arithmetic number, because the mean of its divisors is an integer number (72938321820).

Almost surely, 2^{1010441213131} is an apocalyptic number.

1010441213131 is a deficient number, since it is larger than the sum of its proper divisors (156571935989).

1010441213131 is an equidigital number, since it uses as much as digits as its factorization.

1010441213131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 405894.

The product of its (nonzero) digits is 288, while the sum is 22.

Adding to 1010441213131 its reverse (1313121440101), we get a palindrome (2323562653232).

The spelling of 1010441213131 in words is "one trillion, ten billion, four hundred forty-one million, two hundred thirteen thousand, one hundred thirty-one".