1011001200 has 240 divisors, whose sum is σ = 3560343552. Its totient is φ = 243200000.

The previous prime is 1011001183. The next prime is 1011001217. The reversal of 1011001200 is 21001101.

It is an interprime number because it is at equal distance from previous prime (1011001183) and next prime (1011001217).

It is a tau number, because it is divible by the number of its divisors (240).

It is a Harshad number since it is a multiple of its sum of digits (6).

It is a super Niven number, because it is divisible the sum of any subset of its (nonzero) digits.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 2521000 + ... + 2521400.

Almost surely, 2^1011001200 is an apocalyptic number.

1011001200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1011001200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1780171776).

1011001200 is an abundant number, since it is smaller than the sum of its proper divisors (2549342352).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1011001200 is a wasteful number, since it uses less digits than its factorization.

1011001200 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 624 (or 613 counting only the distinct ones).

The product of its (nonzero) digits is 2, while the sum is 6.

The square root of 1011001200 is about 31796.2450613276. The cubic root of 1011001200 is about 1003.6537008782.

Adding to 1011001200 its reverse (21001101), we get a palindrome (1032002301).

Subtracting from 1011001200 its reverse (21001101), we obtain a palindrome (990000099).

The spelling of 1011001200 in words is "one billion, eleven million, one thousand, two hundred".