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BaseRepresentation
bin10110111111001101101111…
…001001101110001101011101
3111020222011121111020002110122
4112333031233021232031131
5101222420023100000333
6555005112033044325
730203212335543164
oct2677155711561535
9436864544202418
10101101100000093
112a239810282556
12b40a0a19b66a5
134454a3caa1c3b
15ba4d11b06798
hex5bf36f26e35d

101101100000093 has 2 divisors, whose sum is σ = 101101100000094. Its totient is φ = 101101100000092.

The previous prime is 101101100000063. The next prime is 101101100000129. The reversal of 101101100000093 is 390000001101101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 53701152203449 + 47399947796644 = 7328107^2 + 6884762^2 .

It is a cyclic number.

It is not a de Polignac number, because 101101100000093 - 216 = 101101099934557 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101101100000053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50550550000046 + 50550550000047.

It is an arithmetic number, because the mean of its divisors is an integer number (50550550000047).

Almost surely, 2101101100000093 is an apocalyptic number.

It is an amenable number.

101101100000093 is a deficient number, since it is larger than the sum of its proper divisors (1).

101101100000093 is an equidigital number, since it uses as much as digits as its factorization.

101101100000093 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27, while the sum is 17.

Adding to 101101100000093 its reverse (390000001101101), we get a palindrome (491101101101194).

The spelling of 101101100000093 in words is "one hundred one trillion, one hundred one billion, one hundred million, ninety-three", and thus it is an aban number.