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10110113309 is a prime number
BaseRepresentation
bin10010110101001110…
…00001011000011101
3222002120221222012002
421122213001120131
5131201142111214
64351114452045
7505352355002
oct113247013035
928076858162
1010110113309
11431899384a
121b61a34025
13c5176228a
146bca278a9
153e28ae1de
hex25a9c161d

10110113309 has 2 divisors, whose sum is σ = 10110113310. Its totient is φ = 10110113308.

The previous prime is 10110113303. The next prime is 10110113311. The reversal of 10110113309 is 90331101101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7889347684 + 2220765625 = 88822^2 + 47125^2 .

It is a cyclic number.

It is not a de Polignac number, because 10110113309 - 224 = 10093336093 is a prime.

It is a super-2 number, since 2×101101133092 (a number of 21 digits) contains 22 as substring.

Together with 10110113311, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10110113303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055056654 + 5055056655.

It is an arithmetic number, because the mean of its divisors is an integer number (5055056655).

Almost surely, 210110113309 is an apocalyptic number.

It is an amenable number.

10110113309 is a deficient number, since it is larger than the sum of its proper divisors (1).

10110113309 is an equidigital number, since it uses as much as digits as its factorization.

10110113309 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81, while the sum is 20.

The spelling of 10110113309 in words is "ten billion, one hundred ten million, one hundred thirteen thousand, three hundred nine".