10110120131 has 2 divisors, whose sum is σ = 10110120132. Its totient is φ = 10110120130.

The previous prime is 10110120121. The next prime is 10110120161. The reversal of 10110120131 is 13102101101.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10110120131 - 2¹⁴ = 10110103747 is a prime.

It is a super-2 number, since 2×10110120131² (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10110120101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055060065 + 5055060066.

It is an arithmetic number, because the mean of its divisors is an integer number (5055060066).

Almost surely, 2^10110120131 is an apocalyptic number.

10110120131 is a deficient number, since it is larger than the sum of its proper divisors (1).

10110120131 is an equidigital number, since it uses as much as digits as its factorization.

10110120131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6, while the sum is 11.

Adding to 10110120131 its reverse (13102101101), we get a palindrome (23212221232).

The spelling of 10110120131 in words is "ten billion, one hundred ten million, one hundred twenty thousand, one hundred thirty-one".