101120650347141 has 24 divisors (see below), whose sum is σ = 152840285801216. Its totient is φ = 64345442541120.

The previous prime is 101120650347113. The next prime is 101120650347251. The reversal of 101120650347141 is 141743056021101.

101120650347141 is a `hidden beast` number, since 1 + 0 + 1 + 1 + 2 + 0 + 6 + 503 + 4 + 7 + 141 = 666.

It is not a de Polignac number, because 101120650347141 - 2¹⁰ = 101120650346117 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101120650347096 and 101120650347105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101120650349141) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2482442695 + ... + 2482483428.

Almost surely, 2^{101120650347141} is an apocalyptic number.

It is an amenable number.

101120650347141 is a deficient number, since it is larger than the sum of its proper divisors (51719635454075).

101120650347141 is a wasteful number, since it uses less digits than its factorization.

101120650347141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4964926233 (or 4964926230 counting only the distinct ones).

The product of its (nonzero) digits is 20160, while the sum is 36.

The spelling of 101120650347141 in words is "one hundred one trillion, one hundred twenty billion, six hundred fifty million, three hundred forty-seven thousand, one hundred forty-one".