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101121201212002 = 250560600606001
BaseRepresentation
bin10110111111100000011101…
…010001110000101001100010
3111021001002111101012110100121
4112333200131101300221202
5101223232210002241002
6555022234415510454
730204523430200426
oct2677403521605142
9437032441173317
10101121201212002
112a247295950584
12b411b7182842a
1344568c4425b7a
141ad8413d28b86
15ba55db6b6237
hex5bf81d470a62

101121201212002 has 4 divisors (see below), whose sum is σ = 151681801818006. Its totient is φ = 50560600606000.

The previous prime is 101121201211967. The next prime is 101121201212047. The reversal of 101121201212002 is 200212102121101.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 89700579739521 + 11420621472481 = 9471039^2 + 3379441^2 .

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25280300302999 + ... + 25280300303002.

Almost surely, 2101121201212002 is an apocalyptic number.

101121201212002 is a deficient number, since it is larger than the sum of its proper divisors (50560600606004).

101121201212002 is an equidigital number, since it uses as much as digits as its factorization.

101121201212002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 50560600606003.

The product of its (nonzero) digits is 32, while the sum is 16.

Adding to 101121201212002 its reverse (200212102121101), we get a palindrome (301333303333103).

Subtracting 101121201212002 from its reverse (200212102121101), we obtain a palindrome (99090900909099).

The spelling of 101121201212002 in words is "one hundred one trillion, one hundred twenty-one billion, two hundred one million, two hundred twelve thousand, two".

Divisors: 1 2 50560600606001 101121201212002