Base | Representation |
---|---|
bin | 10110111111100000011101… |
… | …010001110000101001100010 |
3 | 111021001002111101012110100121 |
4 | 112333200131101300221202 |
5 | 101223232210002241002 |
6 | 555022234415510454 |
7 | 30204523430200426 |
oct | 2677403521605142 |
9 | 437032441173317 |
10 | 101121201212002 |
11 | 2a247295950584 |
12 | b411b7182842a |
13 | 44568c4425b7a |
14 | 1ad8413d28b86 |
15 | ba55db6b6237 |
hex | 5bf81d470a62 |
101121201212002 has 4 divisors (see below), whose sum is σ = 151681801818006. Its totient is φ = 50560600606000.
The previous prime is 101121201211967. The next prime is 101121201212047. The reversal of 101121201212002 is 200212102121101.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 89700579739521 + 11420621472481 = 9471039^2 + 3379441^2 .
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25280300302999 + ... + 25280300303002.
Almost surely, 2101121201212002 is an apocalyptic number.
101121201212002 is a deficient number, since it is larger than the sum of its proper divisors (50560600606004).
101121201212002 is an equidigital number, since it uses as much as digits as its factorization.
101121201212002 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 50560600606003.
The product of its (nonzero) digits is 32, while the sum is 16.
Adding to 101121201212002 its reverse (200212102121101), we get a palindrome (301333303333103).
Subtracting 101121201212002 from its reverse (200212102121101), we obtain a palindrome (99090900909099).
The spelling of 101121201212002 in words is "one hundred one trillion, one hundred twenty-one billion, two hundred one million, two hundred twelve thousand, two".
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