Base | Representation |
---|---|
bin | 10110111111101001000010… |
… | …001110010110000000001101 |
3 | 111021001222021020001120101120 |
4 | 112333221002032112000031 |
5 | 101223410040204224023 |
6 | 555030400333431153 |
7 | 30205300601155602 |
oct | 2677510216260015 |
9 | 437058236046346 |
10 | 101130411008013 |
11 | 2a250191605642 |
12 | b41390203b4b9 |
13 | 44577314b01ca |
14 | 1ad8a491526a9 |
15 | ba5979ed48e3 |
hex | 5bfa4239600d |
101130411008013 has 16 divisors (see below), whose sum is σ = 135236650157376. Its totient is φ = 67222486828800.
The previous prime is 101130411007943. The next prime is 101130411008027. The reversal of 101130411008013 is 310800114031101.
It is a de Polignac number, because none of the positive numbers 2k-101130411008013 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (101130411008063) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 31453438 + ... + 34519263.
It is an arithmetic number, because the mean of its divisors is an integer number (8452290634836).
Almost surely, 2101130411008013 is an apocalyptic number.
It is an amenable number.
101130411008013 is a deficient number, since it is larger than the sum of its proper divisors (34106239149363).
101130411008013 is an equidigital number, since it uses as much as digits as its factorization.
101130411008013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65974204.
The product of its (nonzero) digits is 288, while the sum is 24.
Adding to 101130411008013 its reverse (310800114031101), we get a palindrome (411930525039114).
The spelling of 101130411008013 in words is "one hundred one trillion, one hundred thirty billion, four hundred eleven million, eight thousand, thirteen".
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