10113110312113 has 16 divisors (see below), whose sum is σ = 11102823280080. Its totient is φ = 9168782708736.

The previous prime is 10113110312099. The next prime is 10113110312131. The reversal of 10113110312113 is 31121301131101.

It can be written as a sum of positive squares in 8 ways, for example, as 770380110369 + 9342730201744 = 877713^2 + 3056588^2 .

It is a cyclic number.

It is not a de Polignac number, because 10113110312113 - 2³⁷ = 9975671358641 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10113110310113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 23474070 + ... + 23901007.

It is an arithmetic number, because the mean of its divisors is an integer number (693926455005).

Almost surely, 2^{10113110312113} is an apocalyptic number.

It is an amenable number.

10113110312113 is a deficient number, since it is larger than the sum of its proper divisors (989712967967).

10113110312113 is a wasteful number, since it uses less digits than its factorization.

10113110312113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 47375556.

The product of its (nonzero) digits is 54, while the sum is 19.

Adding to 10113110312113 its reverse (31121301131101), we get a palindrome (41234411443214).

The spelling of 10113110312113 in words is "ten trillion, one hundred thirteen billion, one hundred ten million, three hundred twelve thousand, one hundred thirteen".