Base | Representation |
---|---|
bin | 1001001100101010010001… |
… | …1001101110000001001111 |
3 | 1022210210201002221121010001 |
4 | 2103022210121232001033 |
5 | 2311143122433022203 |
6 | 33301522115025131 |
7 | 2062435216014010 |
oct | 223124431560117 |
9 | 38723632847101 |
10 | 10113111220303 |
11 | 3249a456a9a83 |
12 | 1173ba459b1a7 |
13 | 58487c0ab590 |
14 | 26d6975cb007 |
15 | 1280ea24d91d |
hex | 932a466e04f |
10113111220303 has 32 divisors (see below), whose sum is σ = 12708231782400. Its totient is φ = 7834217878656.
The previous prime is 10113111220291. The next prime is 10113111220319. The reversal of 10113111220303 is 30302211131101.
It is not a de Polignac number, because 10113111220303 - 241 = 7914087964751 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10113111220903) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 121438 + ... + 4498996.
It is an arithmetic number, because the mean of its divisors is an integer number (397132243200).
Almost surely, 210113111220303 is an apocalyptic number.
10113111220303 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
10113111220303 is a deficient number, since it is larger than the sum of its proper divisors (2595120562097).
10113111220303 is a wasteful number, since it uses less digits than its factorization.
10113111220303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4378111.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 10113111220303 its reverse (30302211131101), we get a palindrome (40415322351404).
The spelling of 10113111220303 in words is "ten trillion, one hundred thirteen billion, one hundred eleven million, two hundred twenty thousand, three hundred three".
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