1011314011 has 2 divisors, whose sum is σ = 1011314012. Its totient is φ = 1011314010.

The previous prime is 1011314009. The next prime is 1011314039. The reversal of 1011314011 is 1104131101.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1011314011 - 2¹ = 1011314009 is a prime.

Together with 1011314009, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1011313982 and 1011314000.

It is not a weakly prime, because it can be changed into another prime (1011314611) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505657005 + 505657006.

It is an arithmetic number, because the mean of its divisors is an integer number (505657006).

Almost surely, 2^1011314011 is an apocalyptic number.

1011314011 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011314011 is an equidigital number, since it uses as much as digits as its factorization.

1011314011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 13.

The square root of 1011314011 is about 31801.1636736771. The cubic root of 1011314011 is about 1003.7572027479.

Adding to 1011314011 its reverse (1104131101), we get a palindrome (2115445112).

The spelling of 1011314011 in words is "one billion, eleven million, three hundred fourteen thousand, eleven".