10113212131 has 4 divisors (see below), whose sum is σ = 11032595064. Its totient is φ = 9193829200.

The previous prime is 10113212129. The next prime is 10113212147. The reversal of 10113212131 is 13121231101.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10113212131 - 2¹ = 10113212129 is a prime.

It is a super-2 number, since 2×10113212131² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10113212101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 459691450 + ... + 459691471.

It is an arithmetic number, because the mean of its divisors is an integer number (2758148766).

Almost surely, 2^10113212131 is an apocalyptic number.

10113212131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

10113212131 is a deficient number, since it is larger than the sum of its proper divisors (919382933).

10113212131 is an equidigital number, since it uses as much as digits as its factorization.

10113212131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 919382932.

The product of its (nonzero) digits is 36, while the sum is 16.

Adding to 10113212131 its reverse (13121231101), we get a palindrome (23234443232).

The spelling of 10113212131 in words is "ten billion, one hundred thirteen million, two hundred twelve thousand, one hundred thirty-one".