Base | Representation |
---|---|
bin | 11101011011110000001… |
… | …11011110011101011101 |
3 | 10120200102111121010012010 |
4 | 32231320013132131131 |
5 | 113032202112242003 |
6 | 2052333314101433 |
7 | 133031522520000 |
oct | 16557007363535 |
9 | 3520374533163 |
10 | 1011332540253 |
11 | 35a9a3943142 |
12 | 14400527a879 |
13 | 744a3075269 |
14 | 36d3d55b537 |
15 | 1b4915e1003 |
hex | eb781de75d |
1011332540253 has 40 divisors (see below), whose sum is σ = 1641485850048. Its totient is φ = 552777943872.
The previous prime is 1011332540177. The next prime is 1011332540287. The reversal of 1011332540253 is 3520452331101.
It is not a de Polignac number, because 1011332540253 - 210 = 1011332539229 is a prime.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 1011332540253.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1011332540753) by changing a digit.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 2886600 + ... + 3217937.
Almost surely, 21011332540253 is an apocalyptic number.
It is an amenable number.
1011332540253 is a deficient number, since it is larger than the sum of its proper divisors (630153309795).
1011332540253 is an frugal number, since it uses more digits than its factorization.
1011332540253 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6104591 (or 6104570 counting only the distinct ones).
The product of its (nonzero) digits is 10800, while the sum is 30.
Adding to 1011332540253 its reverse (3520452331101), we get a palindrome (4531784871354).
The spelling of 1011332540253 in words is "one trillion, eleven billion, three hundred thirty-two million, five hundred forty thousand, two hundred fifty-three".
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