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101141 is a prime number
BaseRepresentation
bin11000101100010101
312010201222
4120230111
511214031
62100125
7600605
oct305425
9163658
10101141
1169a97
124a645
1337061
1428c05
151ee7b
hex18b15

101141 has 2 divisors, whose sum is σ = 101142. Its totient is φ = 101140.

The previous prime is 101119. The next prime is 101149. The reversal of 101141 is 141101.

It is an a-pointer prime, because the next prime (101149) can be obtained adding 101141 to its sum of digits (8).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 96100 + 5041 = 310^2 + 71^2 .

It is an emirp because it is prime and its reverse (141101) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-101141 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50570 + 50571.

It is an arithmetic number, because the mean of its divisors is an integer number (50571).

2101141 is an apocalyptic number.

It is an amenable number.

101141 is a deficient number, since it is larger than the sum of its proper divisors (1).

101141 is an equidigital number, since it uses as much as digits as its factorization.

101141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4, while the sum is 8.

The square root of 101141 is about 318.0267284365. The cubic root of 101141 is about 46.5917562336.

Adding to 101141 its reverse (141101), we get a palindrome (242242).

It can be divided in two parts, 101 and 141, that multiplied together give a palindrome (14241).

The spelling of 101141 in words is "one hundred one thousand, one hundred forty-one", and thus it is an iban number.