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101201203 = 257393779
BaseRepresentation
bin1100000100000…
…11010100110011
321001102112221201
412002003110303
5201401414303
614013032031
72336124145
oct602032463
9231375851
10101201203
1152141a64
1229a85617
1317c7448c
14d624c95
158d4081d
hex6083533

101201203 has 4 divisors (see below), whose sum is σ = 101595240. Its totient is φ = 100807168.

The previous prime is 101201197. The next prime is 101201207. The reversal of 101201203 is 302102101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 101201203 - 25 = 101201171 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 101201203.

It is not an unprimeable number, because it can be changed into a prime (101201207) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 196633 + ... + 197146.

It is an arithmetic number, because the mean of its divisors is an integer number (25398810).

Almost surely, 2101201203 is an apocalyptic number.

101201203 is a deficient number, since it is larger than the sum of its proper divisors (394037).

101201203 is an equidigital number, since it uses as much as digits as its factorization.

101201203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 394036.

The product of its (nonzero) digits is 12, while the sum is 10.

The square root of 101201203 is about 10059.8808641057. The cubic root of 101201203 is about 466.0099879972.

Adding to 101201203 its reverse (302102101), we get a palindrome (403303304).

The spelling of 101201203 in words is "one hundred one million, two hundred one thousand, two hundred three".

Divisors: 1 257 393779 101201203