Base | Representation |
---|---|
bin | 10111000000101010111110… |
… | …001111101110000011110011 |
3 | 111021022202000102011000000222 |
4 | 113000222332033232003303 |
5 | 101231040040033021321 |
6 | 555123110012003255 |
7 | 30213355233064454 |
oct | 2700527617560363 |
9 | 437282012130028 |
10 | 101201211220211 |
11 | 2a278213472a03 |
12 | b425580a6052b |
13 | 44613056531ab |
14 | 1adc24414b12b |
15 | ba77209b03ab |
hex | 5c0abe3ee0f3 |
101201211220211 has 2 divisors, whose sum is σ = 101201211220212. Its totient is φ = 101201211220210.
The previous prime is 101201211220177. The next prime is 101201211220217. The reversal of 101201211220211 is 112022112102101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 101201211220211 - 230 = 101200137478387 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 101201211220211.
It is not a weakly prime, because it can be changed into another prime (101201211220217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50600605610105 + 50600605610106.
It is an arithmetic number, because the mean of its divisors is an integer number (50600605610106).
Almost surely, 2101201211220211 is an apocalyptic number.
101201211220211 is a deficient number, since it is larger than the sum of its proper divisors (1).
101201211220211 is an equidigital number, since it uses as much as digits as its factorization.
101201211220211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32, while the sum is 17.
Adding to 101201211220211 its reverse (112022112102101), we get a palindrome (213223323322312).
The spelling of 101201211220211 in words is "one hundred one trillion, two hundred one billion, two hundred eleven million, two hundred twenty thousand, two hundred eleven".
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