10120307 has 2 divisors, whose sum is σ = 10120308. Its totient is φ = 10120306.

The previous prime is 10120303. The next prime is 10120309. The reversal of 10120307 is 70302101.

It is a strong prime.

It is an emirp because it is prime and its reverse (70302101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10120307 - 2² = 10120303 is a prime.

It is a super-2 number, since 2×10120307² = 204841227548498, which contains 22 as substring.

Together with 10120309, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 10120291 and 10120300.

It is not a weakly prime, because it can be changed into another prime (10120303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5060153 + 5060154.

It is an arithmetic number, because the mean of its divisors is an integer number (5060154).

Almost surely, 2^10120307 is an apocalyptic number.

10120307 is a deficient number, since it is larger than the sum of its proper divisors (1).

10120307 is an equidigital number, since it uses as much as digits as its factorization.

10120307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 42, while the sum is 14.

The square root of 10120307 is about 3181.2429960630. The cubic root of 10120307 is about 216.3040058017.

Adding to 10120307 its reverse (70302101), we get a palindrome (80422408).

The spelling of 10120307 in words is "ten million, one hundred twenty thousand, three hundred seven".