Base | Representation |
---|---|
bin | 101111001000010010… |
… | …1111110011100100011 |
3 | 100200020111200220120202 |
4 | 1132100211332130203 |
5 | 3124234242401034 |
6 | 114254552055415 |
7 | 10212036562016 |
oct | 1362045763443 |
9 | 320214626522 |
10 | 101210122019 |
11 | 39a17525746 |
12 | 1774709456b |
13 | 970c439186 |
14 | 4c81a6737d |
15 | 29755c447e |
hex | 179097e723 |
101210122019 has 2 divisors, whose sum is σ = 101210122020. Its totient is φ = 101210122018.
The previous prime is 101210122009. The next prime is 101210122021. The reversal of 101210122019 is 910221012101.
It is a strong prime.
It is an emirp because it is prime and its reverse (910221012101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 101210122019 - 212 = 101210117923 is a prime.
It is a super-2 number, since 2×1012101220192 (a number of 23 digits) contains 22 as substring.
Together with 101210122021, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (101210122009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50605061009 + 50605061010.
It is an arithmetic number, because the mean of its divisors is an integer number (50605061010).
Almost surely, 2101210122019 is an apocalyptic number.
101210122019 is a deficient number, since it is larger than the sum of its proper divisors (1).
101210122019 is an equidigital number, since it uses as much as digits as its factorization.
101210122019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 20.
The spelling of 101210122019 in words is "one hundred one billion, two hundred ten million, one hundred twenty-two thousand, nineteen".
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