Base | Representation |
---|---|

bin | 11101011101001100111… |

… | …01011001110000101111 |

3 | 10120202102200121012111011 |

4 | 32232212131121300233 |

5 | 113040300132240421 |

6 | 2052542410410051 |

7 | 133060013252302 |

oct | 16564635316057 |

9 | 3522380535434 |

10 | 1012110040111 |

11 | 360262806305 |

12 | 1441a1730927 |

13 | 7459817aa51 |

14 | 36db490ab39 |

15 | 1b4d99c14e1 |

hex | eba6759c2f |

1012110040111 has 2 divisors, whose sum is σ = 1012110040112. Its totient is φ = 1012110040110.

The previous prime is 1012110040093. The next prime is 1012110040153. The reversal of 1012110040111 is 1110400112101.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1012110040111 - 2^{5} = 1012110040079 is a prime.

It is a junction number, because it is equal to *n*+sod(*n*) for *n* = 1012110040091 and 1012110040100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1012110440111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506055020055 + 506055020056.

It is an arithmetic number, because the mean of its divisors is an integer number (506055020056).

Almost surely, 2^{1012110040111} is an apocalyptic number.

1012110040111 is a deficient number, since it is larger than the sum of its proper divisors (1).

1012110040111 is an equidigital number, since it uses as much as digits as its factorization.

1012110040111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8, while the sum is 13.

Adding to 1012110040111 its reverse (1110400112101), we get a palindrome (2122510152212).

The spelling of 1012110040111 in words is "one trillion, twelve billion, one hundred ten million, forty thousand, one hundred eleven".

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