10122113 has 2 divisors, whose sum is σ = 10122114. Its totient is φ = 10122112.

The previous prime is 10122043. The next prime is 10122143. The reversal of 10122113 is 31122101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7139584 + 2982529 = 2672^2 + 1727^2 .

It is an emirp because it is prime and its reverse (31122101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10122113 - 2¹⁶ = 10056577 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10122094 and 10122103.

It is not a weakly prime, because it can be changed into another prime (10122143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5061056 + 5061057.

It is an arithmetic number, because the mean of its divisors is an integer number (5061057).

Almost surely, 2^10122113 is an apocalyptic number.

It is an amenable number.

10122113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10122113 is an equidigital number, since it uses as much as digits as its factorization.

10122113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 10122113 is about 3181.5268347132. The cubic root of 10122113 is about 216.3168717421.

Subtracting from 10122113 its product of nonzero digits (12), we obtain a palindrome (10122101).

Adding to 10122113 its reverse (31122101), we get a palindrome (41244214).

It can be divided in two parts, 1012 and 2113, that added together give a 5-th power (3125 = 5⁵).

The spelling of 10122113 in words is "ten million, one hundred twenty-two thousand, one hundred thirteen".