Base | Representation |
---|---|
bin | 11101011101101111110… |
… | …11101111000100111101 |
3 | 10120210012010020111022021 |
4 | 32232313323233010331 |
5 | 113041400210020123 |
6 | 2053031442120141 |
7 | 133100203151566 |
oct | 16566773570475 |
9 | 3523163214267 |
10 | 1012403204413 |
11 | 3603a3240a57 |
12 | 144263950051 |
13 | 74613b24353 |
14 | 3700182116d |
15 | 1b5055cec5d |
hex | ebb7eef13d |
1012403204413 has 2 divisors, whose sum is σ = 1012403204414. Its totient is φ = 1012403204412.
The previous prime is 1012403204357. The next prime is 1012403204419. The reversal of 1012403204413 is 3144023042101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 895451516089 + 116951688324 = 946283^2 + 341982^2 .
It is a cyclic number.
It is not a de Polignac number, because 1012403204413 - 29 = 1012403203901 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1012403204419) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506201602206 + 506201602207.
It is an arithmetic number, because the mean of its divisors is an integer number (506201602207).
Almost surely, 21012403204413 is an apocalyptic number.
It is an amenable number.
1012403204413 is a deficient number, since it is larger than the sum of its proper divisors (1).
1012403204413 is an equidigital number, since it uses as much as digits as its factorization.
1012403204413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 1012403204413 its reverse (3144023042101), we get a palindrome (4156426246514).
The spelling of 1012403204413 in words is "one trillion, twelve billion, four hundred three million, two hundred four thousand, four hundred thirteen".
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