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10211001113 is a prime number
BaseRepresentation
bin10011000001001111…
…11000001100011001
3222100121210121020102
421200213320030121
5131403004013423
64405121105145
7511016035355
oct114047701431
928317717212
1010211001113
11436a9312a5
121b8b7881b5
13c69626bc1
146cc1aa465
153eb68bc28
hex2609f8319

10211001113 has 2 divisors, whose sum is σ = 10211001114. Its totient is φ = 10211001112.

The previous prime is 10211001019. The next prime is 10211001127. The reversal of 10211001113 is 31110011201.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8545708249 + 1665292864 = 92443^2 + 40808^2 .

It is a cyclic number.

It is not a de Polignac number, because 10211001113 - 228 = 9942565657 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10211001094 and 10211001103.

It is not a weakly prime, because it can be changed into another prime (10211001313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5105500556 + 5105500557.

It is an arithmetic number, because the mean of its divisors is an integer number (5105500557).

Almost surely, 210211001113 is an apocalyptic number.

It is an amenable number.

10211001113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10211001113 is an equidigital number, since it uses as much as digits as its factorization.

10211001113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6, while the sum is 11.

Adding to 10211001113 its reverse (31110011201), we get a palindrome (41321012314).

The spelling of 10211001113 in words is "ten billion, two hundred eleven million, one thousand, one hundred thirteen".