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10215104445391 is a prime number
BaseRepresentation
bin1001010010100110001110…
…1010111111101111001111
31100011112222012012021011011
42110221203222333233033
52314331013214223031
633420430523510051
72103005545066246
oct224514352775717
940145865167134
1010215104445391
11328922417463a
12118b909988327
13591384832741
142745b126195d
1512aab945d6b1
hex94a63abfbcf

10215104445391 has 2 divisors, whose sum is σ = 10215104445392. Its totient is φ = 10215104445390.

The previous prime is 10215104445389. The next prime is 10215104445439. The reversal of 10215104445391 is 19354440151201.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10215104445391 - 21 = 10215104445389 is a prime.

It is a super-3 number, since 3×102151044453913 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 10215104445389, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10215104845391) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5107552222695 + 5107552222696.

It is an arithmetic number, because the mean of its divisors is an integer number (5107552222696).

Almost surely, 210215104445391 is an apocalyptic number.

10215104445391 is a deficient number, since it is larger than the sum of its proper divisors (1).

10215104445391 is an equidigital number, since it uses as much as digits as its factorization.

10215104445391 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 86400, while the sum is 40.

Adding to 10215104445391 its reverse (19354440151201), we get a palindrome (29569544596592).

The spelling of 10215104445391 in words is "ten trillion, two hundred fifteen billion, one hundred four million, four hundred forty-five thousand, three hundred ninety-one".