Base | Representation |
---|---|
bin | 100111000111… |
… | …001100111010 |
3 | 201021220121222 |
4 | 213013030322 |
5 | 10111044424 |
6 | 1003432042 |
7 | 153102314 |
oct | 47071472 |
9 | 21256558 |
10 | 10253114 |
11 | 5873353 |
12 | 3525622 |
13 | 217cb41 |
14 | 150c7b4 |
15 | d77e5e |
hex | 9c733a |
10253114 has 4 divisors (see below), whose sum is σ = 15379674. Its totient is φ = 5126556.
The previous prime is 10253053. The next prime is 10253149. The reversal of 10253114 is 41135201.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 41135201 = 23 ⋅1788487.
It can be written as a sum of positive squares in only one way, i.e., 9504889 + 748225 = 3083^2 + 865^2 .
It is a junction number, because it is equal to n+sod(n) for n = 10253092 and 10253101.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2563277 + ... + 2563280.
Almost surely, 210253114 is an apocalyptic number.
10253114 is a deficient number, since it is larger than the sum of its proper divisors (5126560).
10253114 is an equidigital number, since it uses as much as digits as its factorization.
10253114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5126559.
The product of its (nonzero) digits is 120, while the sum is 17.
The square root of 10253114 is about 3202.0484068796. The cubic root of 10253114 is about 217.2460699722.
Adding to 10253114 its reverse (41135201), we get a palindrome (51388315).
The spelling of 10253114 in words is "ten million, two hundred fifty-three thousand, one hundred fourteen".
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