Base | Representation |
---|---|
bin | 110000000000101001… |
… | …1100100001001101101 |
3 | 100212010021221121200222 |
4 | 1200001103210021231 |
5 | 3142122341334013 |
6 | 115210342501125 |
7 | 10306641032663 |
oct | 1400123441155 |
9 | 325107847628 |
10 | 103101121133 |
11 | 3a7a799332a |
12 | 17b944347a5 |
13 | 995113ab6a |
14 | 4dc0c6ac33 |
15 | 2a36605508 |
hex | 18014e426d |
103101121133 has 2 divisors, whose sum is σ = 103101121134. Its totient is φ = 103101121132.
The previous prime is 103101121099. The next prime is 103101121153. The reversal of 103101121133 is 331121101301.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 100107061609 + 2994059524 = 316397^2 + 54718^2 .
It is a cyclic number.
It is not a de Polignac number, because 103101121133 - 214 = 103101104749 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (103101121153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51550560566 + 51550560567.
It is an arithmetic number, because the mean of its divisors is an integer number (51550560567).
Almost surely, 2103101121133 is an apocalyptic number.
It is an amenable number.
103101121133 is a deficient number, since it is larger than the sum of its proper divisors (1).
103101121133 is an equidigital number, since it uses as much as digits as its factorization.
103101121133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 103101121133 its reverse (331121101301), we get a palindrome (434222222434).
The spelling of 103101121133 in words is "one hundred three billion, one hundred one million, one hundred twenty-one thousand, one hundred thirty-three".
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