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103422525137 is a prime number
BaseRepresentation
bin110000001010001110…
…1100111111011010001
3100212221200201122002222
41200110131213323101
53143302131301022
6115302303350425
710320622646621
oct1402435477321
9325850648088
10103422525137
113a952356978
1218063bb2415
1399a28c1149
145011812881
152a54941242
hex1814767ed1

103422525137 has 2 divisors, whose sum is σ = 103422525138. Its totient is φ = 103422525136.

The previous prime is 103422525127. The next prime is 103422525149. The reversal of 103422525137 is 731525224301.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 77840442001 + 25582083136 = 278999^2 + 159944^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-103422525137 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 103422525097 and 103422525106.

It is not a weakly prime, because it can be changed into another prime (103422525127) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51711262568 + 51711262569.

It is an arithmetic number, because the mean of its divisors is an integer number (51711262569).

Almost surely, 2103422525137 is an apocalyptic number.

It is an amenable number.

103422525137 is a deficient number, since it is larger than the sum of its proper divisors (1).

103422525137 is an equidigital number, since it uses as much as digits as its factorization.

103422525137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 50400, while the sum is 35.

Adding to 103422525137 its reverse (731525224301), we get a palindrome (834947749438).

The spelling of 103422525137 in words is "one hundred three billion, four hundred twenty-two million, five hundred twenty-five thousand, one hundred thirty-seven".