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10388373675551 is a prime number
BaseRepresentation
bin1001011100101011101101…
…0100101001111000011111
31100210010012121211010221222
42113022323110221320133
52330200342130104201
634032204124443555
72121351404203544
oct227127324517037
940703177733858
1010388373675551
11334575912a813
1211b94053a95bb
135a4808b87631
1427cb2b184bcb
1513035acce91b
hex972bb529e1f

10388373675551 has 2 divisors, whose sum is σ = 10388373675552. Its totient is φ = 10388373675550.

The previous prime is 10388373675529. The next prime is 10388373675583. The reversal of 10388373675551 is 15557637388301.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10388373675551 is a prime.

It is a super-4 number, since 4×103883736755514 (a number of 53 digits) contains 4444 as substring.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10388373677551) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5194186837775 + 5194186837776.

It is an arithmetic number, because the mean of its divisors is an integer number (5194186837776).

Almost surely, 210388373675551 is an apocalyptic number.

10388373675551 is a deficient number, since it is larger than the sum of its proper divisors (1).

10388373675551 is an equidigital number, since it uses as much as digits as its factorization.

10388373675551 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 63504000, while the sum is 62.

The spelling of 10388373675551 in words is "ten trillion, three hundred eighty-eight billion, three hundred seventy-three million, six hundred seventy-five thousand, five hundred fifty-one".