Base | Representation |
---|---|
bin | 1001011101011011111110… |
… | …1001011000110000110000 |
3 | 1100211100122122112120211101 |
4 | 2113112333221120300300 |
5 | 2330403411231334300 |
6 | 34042145555454144 |
7 | 2122320452524165 |
oct | 227267751306060 |
9 | 40740578476741 |
10 | 10401331121200 |
11 | 33501a828a488 |
12 | 11bba208b7354 |
13 | 5a5ac24a9c36 |
14 | 27d5d9dd406c |
15 | 130868627b6a |
hex | 975bfa58c30 |
10401331121200 has 60 divisors (see below), whose sum is σ = 24989513577448. Its totient is φ = 4160479910400.
The previous prime is 10401331121131. The next prime is 10401331121219. The reversal of 10401331121200 is 212113310401.
It is a super-3 number, since 3×104013311212003 (a number of 40 digits) contains 333 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 53230879 + ... + 53425921.
Almost surely, 210401331121200 is an apocalyptic number.
10401331121200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
10401331121200 is an abundant number, since it is smaller than the sum of its proper divisors (14588182456248).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
10401331121200 is a wasteful number, since it uses less digits than its factorization.
10401331121200 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 328382 (or 328371 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 10401331121200 its reverse (212113310401), we get a palindrome (10613444431601).
The spelling of 10401331121200 in words is "ten trillion, four hundred one billion, three hundred thirty-one million, one hundred twenty-one thousand, two hundred".
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