Base | Representation |
---|---|
bin | 11001000000101110011011… |
… | …001000011110111000110111 |
3 | 112102110222211112020200112211 |
4 | 121000232123020132320313 |
5 | 103404224032042010012 |
6 | 1025541433313554251 |
7 | 32112211401355642 |
oct | 3100563310367067 |
9 | 472428745220484 |
10 | 110001010110007 |
11 | 32060191539855 |
12 | 10406b23875987 |
13 | 494c08763b2a3 |
14 | 1d24112160a59 |
15 | cab5a323e6a7 |
hex | 640b9b21ee37 |
110001010110007 has 2 divisors, whose sum is σ = 110001010110008. Its totient is φ = 110001010110006.
The previous prime is 110001010109957. The next prime is 110001010110073. The reversal of 110001010110007 is 700011010100011.
It is a weak prime.
It is an emirp because it is prime and its reverse (700011010100011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 110001010110007 - 223 = 110001001721399 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110001010110077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55000505055003 + 55000505055004.
It is an arithmetic number, because the mean of its divisors is an integer number (55000505055004).
Almost surely, 2110001010110007 is an apocalyptic number.
110001010110007 is a deficient number, since it is larger than the sum of its proper divisors (1).
110001010110007 is an equidigital number, since it uses as much as digits as its factorization.
110001010110007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7, while the sum is 13.
Adding to 110001010110007 its reverse (700011010100011), we get a palindrome (810012020210018).
The spelling of 110001010110007 in words is "one hundred ten trillion, one billion, ten million, one hundred ten thousand, seven".
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