1100010113 has 2 divisors, whose sum is σ = 1100010114. Its totient is φ = 1100010112.

The previous prime is 1100010103. The next prime is 1100010151. The reversal of 1100010113 is 3110100011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 870427009 + 229583104 = 29503^2 + 15152^2 .

It is an emirp because it is prime and its reverse (3110100011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1100010113 - 2⁴ = 1100010097 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1100010113.

It is not a weakly prime, because it can be changed into another prime (1100010103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550005056 + 550005057.

It is an arithmetic number, because the mean of its divisors is an integer number (550005057).

Almost surely, 2^1100010113 is an apocalyptic number.

It is an amenable number.

1100010113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100010113 is an equidigital number, since it uses as much as digits as its factorization.

1100010113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3, while the sum is 8.

The square root of 1100010113 is about 33166.4003624150. The cubic root of 1100010113 is about 1032.2832789160.

Adding to 1100010113 its reverse (3110100011), we get a palindrome (4210110124).

The spelling of 1100010113 in words is "one billion, one hundred million, ten thousand, one hundred thirteen".