Base | Representation |
---|---|
bin | 10000000000100011000… |
… | …100111000011001010101 |
3 | 10220011112212102212201011 |
4 | 100000203010320121111 |
5 | 121011001112004114 |
6 | 2201213511132221 |
7 | 142323335435113 |
oct | 20004304703125 |
9 | 3804485385634 |
10 | 1100100109909 |
11 | 394605918059 |
12 | 159259374071 |
13 | 7c97b759ac8 |
14 | 3b3608c6ab3 |
15 | 1d9396781c4 |
hex | 10023138655 |
1100100109909 has 2 divisors, whose sum is σ = 1100100109910. Its totient is φ = 1100100109908.
The previous prime is 1100100109897. The next prime is 1100100110017. The reversal of 1100100109909 is 9099010010011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 916442436100 + 183657673809 = 957310^2 + 428553^2 .
It is an emirp because it is prime and its reverse (9099010010011) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1100100109909 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1100100199909) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550050054954 + 550050054955.
It is an arithmetic number, because the mean of its divisors is an integer number (550050054955).
Almost surely, 21100100109909 is an apocalyptic number.
It is an amenable number.
1100100109909 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100100109909 is an equidigital number, since it uses as much as digits as its factorization.
1100100109909 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 729, while the sum is 31.
The spelling of 1100100109909 in words is "one trillion, one hundred billion, one hundred million, one hundred nine thousand, nine hundred nine".
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