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1100101121023 is a prime number
BaseRepresentation
bin10000000000100011001…
…000101111001111111111
310220011112221100020200211
4100000203020233033333
5121011001341333043
62201213544533251
7142323350146012
oct20004310571777
93804487306624
101100101121023
11394606448793
12159259781227
137c97ba220b8
143b360aab379
151d9397c7a9d
hex1002322f3ff

1100101121023 has 2 divisors, whose sum is σ = 1100101121024. Its totient is φ = 1100101121022.

The previous prime is 1100101120997. The next prime is 1100101121059. The reversal of 1100101121023 is 3201211010011.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1100101121023 - 29 = 1100101120511 is a prime.

It is a super-2 number, since 2×11001011210232 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1100101120994 and 1100101121012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1100101121723) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550050560511 + 550050560512.

It is an arithmetic number, because the mean of its divisors is an integer number (550050560512).

Almost surely, 21100101121023 is an apocalyptic number.

1100101121023 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100101121023 is an equidigital number, since it uses as much as digits as its factorization.

1100101121023 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 1100101121023 its reverse (3201211010011), we get a palindrome (4301312131034).

The spelling of 1100101121023 in words is "one trillion, one hundred billion, one hundred one million, one hundred twenty-one thousand, twenty-three".