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BaseRepresentation
bin1010000000010110010101…
…0100011011101010000001
31102221200210100101102000111
42200011211110123222001
52420220233420200113
635221501330151321
72213542534320115
oct240054524335201
942850710342014
1011001111100033
1135615aa4658aa
121298109a22541
1361a5286901b2
142a0656d63745
1514126ded413d
hexa016551ba81

11001111100033 has 2 divisors, whose sum is σ = 11001111100034. Its totient is φ = 11001111100032.

The previous prime is 11001111100013. The next prime is 11001111100037. The reversal of 11001111100033 is 33000111110011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7249943975184 + 3751167124849 = 2692572^2 + 1936793^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11001111100033 is a prime.

It is a zygodrome in base 10.

It is a junction number, because it is equal to n+sod(n) for n = 11001111099986 and 11001111100022.

It is not a weakly prime, because it can be changed into another prime (11001111100037) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500555550016 + 5500555550017.

It is an arithmetic number, because the mean of its divisors is an integer number (5500555550017).

Almost surely, 211001111100033 is an apocalyptic number.

It is an amenable number.

11001111100033 is a deficient number, since it is larger than the sum of its proper divisors (1).

11001111100033 is an equidigital number, since it uses as much as digits as its factorization.

11001111100033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9, while the sum is 13.

Adding to 11001111100033 its reverse (33000111110011), we get a palindrome (44001222210044).

The spelling of 11001111100033 in words is "eleven trillion, one billion, one hundred eleven million, one hundred thousand, thirty-three".