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11001111100823 is a prime number
BaseRepresentation
bin1010000000010110010101…
…0100011011110110010111
31102221200210100101110002202
42200011211110123312113
52420220233420211243
635221501330155115
72213542534322324
oct240054524336627
942850710343082
1011001111100823
1135615aa466458
121298109a22a9b
1361a52869066c
142a0656d63b4b
1514126ded44b8
hexa016551bd97

11001111100823 has 2 divisors, whose sum is σ = 11001111100824. Its totient is φ = 11001111100822.

The previous prime is 11001111100807. The next prime is 11001111100867. The reversal of 11001111100823 is 32800111110011.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11001111100823 - 24 = 11001111100807 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11001111100795 and 11001111100804.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11001111103823) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500555550411 + 5500555550412.

It is an arithmetic number, because the mean of its divisors is an integer number (5500555550412).

Almost surely, 211001111100823 is an apocalyptic number.

11001111100823 is a deficient number, since it is larger than the sum of its proper divisors (1).

11001111100823 is an equidigital number, since it uses as much as digits as its factorization.

11001111100823 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 20.

Adding to 11001111100823 its reverse (32800111110011), we get a palindrome (43801222210834).

The spelling of 11001111100823 in words is "eleven trillion, one billion, one hundred eleven million, one hundred thousand, eight hundred twenty-three".