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110012113 is a prime number
BaseRepresentation
bin1101000111010…
…10011011010001
321200000012020201
412203222123101
5211130341423
614525535201
72504042011
oct643523321
9250005221
10110012113
115710a802
1230a14501
1319a3aa33
1410879c41
1599d12ad
hex68ea6d1

110012113 has 2 divisors, whose sum is σ = 110012114. Its totient is φ = 110012112.

The previous prime is 110012081. The next prime is 110012141. The reversal of 110012113 is 311210011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 84327489 + 25684624 = 9183^2 + 5068^2 .

It is a cyclic number.

It is not a de Polignac number, because 110012113 - 25 = 110012081 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 110012113.

It is not a weakly prime, because it can be changed into another prime (110012183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55006056 + 55006057.

It is an arithmetic number, because the mean of its divisors is an integer number (55006057).

Almost surely, 2110012113 is an apocalyptic number.

It is an amenable number.

110012113 is a deficient number, since it is larger than the sum of its proper divisors (1).

110012113 is an equidigital number, since it uses as much as digits as its factorization.

110012113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 10.

The square root of 110012113 is about 10488.6659304222. The cubic root of 110012113 is about 479.1595724755.

Adding to 110012113 its reverse (311210011), we get a palindrome (421222124).

The spelling of 110012113 in words is "one hundred ten million, twelve thousand, one hundred thirteen".