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110021220014014 = 255219963885167
BaseRepresentation
bin11001000001000001001111…
…101111001001011110111110
3112102112220222222202011222001
4121001001033233021132332
5103410041424310422024
61025555014542212514
732113525252616611
oct3101011757113676
9472486888664861
10110021220014014
11320688124a5861
121040aa23b8413a
134950c5865a17a
141d250ac286178
15cabd8761e244
hex64104fbc97be

110021220014014 has 8 divisors (see below), whose sum is σ = 165061721693088. Its totient is φ = 55000646116320.

The previous prime is 110021220014003. The next prime is 110021220014051. The reversal of 110021220014014 is 410410022120011.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 110021220013982 and 110021220014000.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4981931542 + ... + 4981953625.

It is an arithmetic number, because the mean of its divisors is an integer number (20632715211636).

Almost surely, 2110021220014014 is an apocalyptic number.

110021220014014 is a deficient number, since it is larger than the sum of its proper divisors (55040501679074).

110021220014014 is an equidigital number, since it uses as much as digits as its factorization.

110021220014014 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9963890690.

The product of its (nonzero) digits is 128, while the sum is 19.

Adding to 110021220014014 its reverse (410410022120011), we get a palindrome (520431242134025).

The spelling of 110021220014014 in words is "one hundred ten trillion, twenty-one billion, two hundred twenty million, fourteen thousand, fourteen".

Divisors: 1 2 5521 11042 9963885167 19927770334 55010610007007 110021220014014