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110022219973 is a prime number
BaseRepresentation
bin110011001110111010…
…1011101100011000101
3101111222122012212110001
41212131311131203011
53300311142014343
6122313222001301
710643311303501
oct1463565354305
9344878185401
10110022219973
1142729747326
12193a6276231
13a4b4ca9913
14547a129301
152cde03644d
hex199dd5d8c5

110022219973 has 2 divisors, whose sum is σ = 110022219974. Its totient is φ = 110022219972.

The previous prime is 110022219971. The next prime is 110022220039. The reversal of 110022219973 is 379912220011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 95050739809 + 14971480164 = 308303^2 + 122358^2 .

It is a cyclic number.

It is not a de Polignac number, because 110022219973 - 21 = 110022219971 is a prime.

Together with 110022219971, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110022219971) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55011109986 + 55011109987.

It is an arithmetic number, because the mean of its divisors is an integer number (55011109987).

Almost surely, 2110022219973 is an apocalyptic number.

It is an amenable number.

110022219973 is a deficient number, since it is larger than the sum of its proper divisors (1).

110022219973 is an equidigital number, since it uses as much as digits as its factorization.

110022219973 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13608, while the sum is 37.

Adding to 110022219973 its reverse (379912220011), we get a palindrome (489934439984).

The spelling of 110022219973 in words is "one hundred ten billion, twenty-two million, two hundred nineteen thousand, nine hundred seventy-three".