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11003001323 = 83351737693
BaseRepresentation
bin10100011111101010…
…00111100111101011
31001101211002101021112
422033311013213223
5140013232020243
65015452300535
7536443653026
oct121765074753
931354071245
1011003001323
1147369a8826
122170a7174b
131064738792
147654521bd
15445e83818
hex28fd479eb

11003001323 has 8 divisors (see below), whose sum is σ = 11139029328. Its totient is φ = 10867055904.

The previous prime is 11003001319. The next prime is 11003001371. The reversal of 11003001323 is 32310030011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11003001323 - 22 = 11003001319 is a prime.

It is a super-2 number, since 2×110030013232 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11003001298 and 11003001307.

It is not an unprimeable number, because it can be changed into a prime (11003001313) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 273065 + ... + 310757.

It is an arithmetic number, because the mean of its divisors is an integer number (1392378666).

Almost surely, 211003001323 is an apocalyptic number.

11003001323 is a deficient number, since it is larger than the sum of its proper divisors (136028005).

11003001323 is an equidigital number, since it uses as much as digits as its factorization.

11003001323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 41293.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 11003001323 its reverse (32310030011), we get a palindrome (43313031334).

The spelling of 11003001323 in words is "eleven billion, three million, one thousand, three hundred twenty-three".

Divisors: 1 83 3517 37693 291911 3128519 132566281 11003001323