1101001000993 has 2 divisors, whose sum is σ = 1101001000994. Its totient is φ = 1101001000992.

The previous prime is 1101001000969. The next prime is 1101001001017. The reversal of 1101001000993 is 3990001001011.

It is a balanced prime because it is at equal distance from previous prime (1101001000969) and next prime (1101001001017).

It can be written as a sum of positive squares in only one way, i.e., 599669030689 + 501331970304 = 774383^2 + 708048^2 .

It is a cyclic number.

It is not a de Polignac number, because 1101001000993 - 2¹³ = 1101000992801 is a prime.

It is not a weakly prime, because it can be changed into another prime (1101001000493) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550500500496 + 550500500497.

It is an arithmetic number, because the mean of its divisors is an integer number (550500500497).

Almost surely, 2^{1101001000993} is an apocalyptic number.

It is an amenable number.

1101001000993 is a deficient number, since it is larger than the sum of its proper divisors (1).

1101001000993 is an equidigital number, since it uses as much as digits as its factorization.

1101001000993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 243, while the sum is 25.

The spelling of 1101001000993 in words is "one trillion, one hundred one billion, one million, nine hundred ninety-three", and thus it is an aban number.