Base | Representation |
---|---|
bin | 11001000010010100000001… |
… | …111111100100111011101110 |
3 | 112102212102102212221220101000 |
4 | 121002110001333210323232 |
5 | 103413021001130323433 |
6 | 1030103515231301130 |
7 | 32123123113256250 |
oct | 3102240177447356 |
9 | 472772385856330 |
10 | 110110110011118 |
11 | 320a248759a288 |
12 | 104240b107a7a6 |
13 | 49594535087a9 |
14 | 1d2950199dcd0 |
15 | cae33b2db113 |
hex | 642501fe4eee |
110110110011118 has 64 divisors (see below), whose sum is σ = 279808356096000. Its totient is φ = 31441622802912.
The previous prime is 110110110011117. The next prime is 110110110011137. The reversal of 110110110011118 is 811110011011011.
110110110011118 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a self number, because there is not a number n which added to its sum of digits gives 110110110011118.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (110110110011113) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 84578278 + ... + 85870281.
It is an arithmetic number, because the mean of its divisors is an integer number (4372005564000).
Almost surely, 2110110110011118 is an apocalyptic number.
110110110011118 is a gapful number since it is divisible by the number (18) formed by its first and last digit.
110110110011118 is an abundant number, since it is smaller than the sum of its proper divisors (169698246084882).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
110110110011118 is a wasteful number, since it uses less digits than its factorization.
110110110011118 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 170450286 (or 170450280 counting only the distinct ones).
The product of its (nonzero) digits is 8, while the sum is 18.
Adding to 110110110011118 its reverse (811110011011011), we get a palindrome (921220121022129).
The spelling of 110110110011118 in words is "one hundred ten trillion, one hundred ten billion, one hundred ten million, eleven thousand, one hundred eighteen".
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