Base | Representation |
---|---|
bin | 1010000001100000111000… |
… | …0100000000010000101001 |
3 | 1110000121102221110001221121 |
4 | 2200120032010000100221 |
5 | 2421032224213342301 |
6 | 35235011125335241 |
7 | 2215151451262660 |
oct | 240301604002051 |
9 | 43017387401847 |
10 | 11021122012201 |
11 | 356a039068344 |
12 | 129bb73567521 |
13 | 61c3973b8922 |
14 | 2a15d4889dd7 |
15 | 141a40ba83a1 |
hex | a060e100429 |
11021122012201 has 4 divisors (see below), whose sum is σ = 12595568013952. Its totient is φ = 9446676010452.
The previous prime is 11021122012181. The next prime is 11021122012217. The reversal of 11021122012201 is 10221022112011.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11021122012201 - 221 = 11021119915049 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11021122012261) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 787223000865 + ... + 787223000878.
It is an arithmetic number, because the mean of its divisors is an integer number (3148892003488).
Almost surely, 211021122012201 is an apocalyptic number.
It is an amenable number.
11021122012201 is a deficient number, since it is larger than the sum of its proper divisors (1574446001751).
11021122012201 is an equidigital number, since it uses as much as digits as its factorization.
11021122012201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1574446001750.
The product of its (nonzero) digits is 32, while the sum is 16.
Adding to 11021122012201 its reverse (10221022112011), we get a palindrome (21242144124212).
The spelling of 11021122012201 in words is "eleven trillion, twenty-one billion, one hundred twenty-two million, twelve thousand, two hundred one".
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